2) If the length of a rectangle is reduced by 3 cms and breadth increased by 2 cms, it’s area remains same. But if the length is increased by 2 cms and breadth reduced by 1 cm, then too the area remains same. Find the length and the breadth of the rectangle.
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Let the breadth of the rectangle be Xcm
Then, the length of the rectangle be (x+3)cm
∴ Area of the rectangle =(x+3)×xcm 2 −−−−−(1)
Given that
Length is increased by 9=x+3+9=x+12cm
and, breadth is reduced by 3=x−3cm
Now,
Area of new rectangle (x+12)×(x−3)cm 2 −−−−−(2)
But in the given question we have given that the both area is same
then we can get
(x+3)×x=(x+12)×(x−3)
⇒x 2 +3x=x 2+12x−3x−36
⇒6x=36
∴x=6
Now,fromequation(1)
Areaoftherectangle=(x+3)×x
=(6+3)6
=54cmsquare
Hence proved//
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