Math, asked by joshpadwa100, 5 months ago


2. If the perimeter of the rectangle is 32dm and its width is 7dm, what is the length of the rectangle?
3. The circumference of a circle is 12. Find the radius.​

Answers

Answered by rskinner2r5
1

Answer:

We know that  Perimeter=2×Length+2×Width  

So

2×Width=32−(2×9cm)=14cm  

And therefore

Width=14÷2cm=7cm  

Recalling the definition of area, we know:

Area=Length×Width=9cm×7cm=63cm²

Step-by-step explanation:

i dont have one

Answered by prabhcutie13
2

2. Answer:

Length= 9dm

Step-by-step explanation:

Perimeter= l+b+l+b

Width/bredth= 7dm

Length= ?

Perimeter= 32dm

32= l+l+7+7

32= 2l+14

2l= 32-14

2l=18

l= 18/2

l= 9

Length= 9dm

3. Answer:

6 cm

Explanation:

If r is the radius of a circle, then its circumference is 2πr and area is πr2 . or r=12π2π=6 cm. As such radius is 6 cm and diameter being double of radius, diameter is 2×6=12 cm.

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