Question

2. If the polynomials 2x + x + 3x - 6 and x + x - 4x + k leave the same remainder when divided by(x - 2), find the
numerical value of K.

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Answer 1

X-2

x=2

P(x) =2x+x+3x-6. P(x) =x+x-4x+k

P(2) =2(2)+2+3(2)-6. P(x) =2+2-4(2)+k

P(2)=4+2+6-6. P(x) =2+2-8+k

P(2)=6+6-6. P(x) =4-8+k

P(2)=12-6. P(x) =-4+k

P(2)=6

2x+x+3x-6=x+x-4x+k

6=-4+k

6+4=k

10=k

Hope it will help you