Question

2. If the product of two zeroes of polynomial 2x3 + 3x2 – 5x – 6 is 3, then find its trd zero

Answer 1

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Answer 2

Answer:

The third zero is 1.

Step-by-step explanation:

Given the polynomial

$P(x)=2x^3+3x^2-5x-6$

The product of two zeroes is 3 we have to find the third zero

$P(x)=2x^3+3x^2-5x-6$

$\text{Product of zeroes is }\frac{-d}{a}=-(\frac{-6}{2})=3$

$abc=3$

As product of two zeroes is 3

Let ab=3

Therefore,

3c=3

⇒ c=1

hence, the third zero is 1.