2) If the sum of the ages of the father and sons is 100.if 5 years ago the fathers age was5
times the sons age the then find their present ages.(give answer in detail and correct i will give you brainist mark)
Answers
Step-by-step explanation:
Let the present age of son be x
And, Present age of father be y
Given, Sum of ages of father and son is 100
⇢ x + y = 100.....(i)
Five years ago:-
Age of son = x - 5
Age of father = y - 5
5 years ago, the father was 5 times as old as his son
⇢ y - 5 = 5(x - 5)
⇢ y - 5 = 5x - 25
⇢ y - 5x = -25 + 5
⇢ y - 5x = -20.......(ii)
Subtract equation (ii) from (i)
⇢ x + y - (y - 5x) = 100 - (-20)
⇢ x + y - y + 5x = 100 + 20
⇢ 6x = 120
⇢ x = = 20
Substitute x = 20 in equation (i)
⇢ x + y = 100
⇢ 20 + y = 100
⇢ y = 100 - 20 = 80
Therefore:-
⇝ Present age of son = 20 years
⇝ Present age of father = 80 years
2) If the sum of the ages of the father and sons is 100.if 5 years ago the fathers age was5
2) If the sum of the ages of the father and sons is 100.if 5 years ago the fathers age was5times the sons age the then find their present ages.(give answer in detail and correct i will give you brainist mark)
Let the present age of son be x
And, Present age of father be y
Given, Sum of ages of father and son is 100
⇢ x + y = 100.....(i)
Five years ago:-
Age of son = x - 5
Age of father = y - 5
5 years ago, the father was 5 times as old as his son
Subtract equation (ii) from (i)
Substitute x = 20 in equation (i)
Therefore:-