Question

2. If the sum of the zeroes of the polynomial p(x) = (k2 - 14) x2 - 2x - 12 is 1,
then find the value of k.
3. For what value of k, the pair of equations 4x - 3y = 92Yt ky
11 has no solution​

Answer 1

Step-by-step explanation:

sum of zeros of polynomial = α + β = -b/a = 1

$\alpha + \beta = \frac{ - b}{a} = 1 \\ \frac{ - ( - 2)}{ {k}^{2} - 14 } = 1 \\ \frac{2}{ {k}^{2} - 14 } = 1 \\ {k}^{2} - 14 = 2 \\ {k}^{2} = 14 + 2 \\ {k}^{2} = 16 \\ k = \sqrt{16} \\ k = 4$

Hope you get your answer