Question

2. If the sum of three consecutive odd natural numbers is 57.what is the first number​

Answer 1

As the numbers are consecutive odd natural numbers,

And

Let us assume that three continuous odd natural numbers are

n+1,n+3,n+5

respectively.

Now ,

According to question:-)

$(n + 1 )+ (n + 3 )+ (n + 5) = 57 \\ \\ 3n + 9 = 57 \\ \\ 3n = 57 - 9 \\ \\ 3n = 48 \\ \\ n = \frac{ \cancel{48}}{ \cancel 3} \\ \\ \boxed{ \boxed{ \red{n = 16}}}$

Now putting the value of n

1st number = 17

2nd number = 19

3rd number = 21.

Answer 2

Answer:

Let us assume that three continuous odd natural numbers are

n+1,n+3,n+5

respectively.

Now ,

According to question:-)

\begin{gathered}(n + 1 )+ (n + 3 )+ (n + 5) = 57 \\ \\ 3n + 9 = 57 \\ \\ 3n = 57 - 9 \\ \\ 3n = 48 \\ \\ n = \frac{ \cancel{48}}{ \cancel 3} \\ \\ \boxed{ \boxed{ \red{n = 16}}}\end{gathered}

(n+1)+(n+3)+(n+5)=57

3n+9=57

3n=57−9

3n=48

n=

3

48

n=16

Now putting the value of n

1st number = 17

2nd number = 19

3rd number = 21.

Step-by-step explanation:

hope it helps you