2.If the sum of zeroes of polynomial p(x)=kx^(2)+x-5 is 6 then the value of k is: (a) 1/2 (b) 1/4 (c) -1/6 (d) -1/4
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Answer:
k = -1/6
Step-by-step explanation:
if ax^2 + bx + c =0
sum of zeros is
alpha + beta = -b/a
b = 1 , a = k
6 = -1/k
k = -1/6
thanks..
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