Question

2. If the sum of zeros of the polynomial p(x)= 24x³-
2ax²+29x-6 is 23/12, then find the value of a.
3. Find the zeros of the polynomial 2x³ + 5x²-28x-15.​

Answer 1

Answer23:

Step-by-step explanation

24x³- 2ax²+29x-6

y+β+∝= -b/a

23/12=2a/24

a=23

Answer 2

Step-by-step explanation:

(1).p(x)= 24x³-2ax²+29x-6=0

alpha+beeta+gama=-b/a=23/12

-(-2a)/24=23/12

2a/24=23/12

a/12=23/12

a=23.

(2).2x³+5x²-28x-15=0

sum of all 3zeroes=-b/a=-5/2.

alphabeeta+beetagama+gamaalpha=c/a=-2/2=-1.

product of all 3zeroes=-d/a=15/2.

-5/2,-1,15/2 are the zeroes of polynomial 2x³+5x²-28x-15.