Question

2.
If the zeroes of a polynomial x-3x++x+1 are (a-6), a and (a fb). Find the values of a and b.
3.
Solve
2x-y+4 = 0
2x+y-8 = 0​

Answer 1

Answer:

a−b,a,a+b are zeroes of x3−3x2+x+1

⇒a−b+a+a+b= sum of zeroes = 3

⇒3a=3

⇒a=1

(a−b)(a)(a+b)= product of zeroes =−1

⇒(1−b)(1+b)=−1

⇒1−b2=−1

⇒b2=2

⇒b=±2

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