Question

2. If x = 0 and y =-1, find the value of : (i) xy2 – x2y + x (ii) x2 - 2y2 - 5 ​

Answer 1

$1) \: x {y}^{2} - {x}^{2} y + x$

$= 0( { - 1)}^{2} - ( {0)}^{2} \times - 1 + 0$

$= 0 - 0 + 0$

$= 0$

$2) \: {x}^{2} - 2 {y}^{2} - 5$

$= ( {0)}^{2} - 2( - 1) ^{2} - 5$

$= 0 - 2 - 5$

$= - 7$

Answer 2

Answer:

xy ^2 − x^2^y+x

= 0( - 1 + 0=0(−1)

2 −(0) 2 × − 1 + 0

= 0 - 0 + 0 = 0.

$thanks$