Math, asked by sunilkrmishra1985, 4 days ago

2. If x = 0 and y = 3, evaluate: (a) 8x2 – 7xy +3 ​

Answers

Answered by mettahendre
0

Answer:

3

Step-by-step explanation:

8x² -7xy +3

put value of x=0 and y=3 in above equation

= 8(0)² -7×0×3 +3

= 0 -0 +3

= 3

Answered by mahakulkarpooja615
1

Answer:

The value of 8x^{2} -7xy+3 at x=0, y=3 is 3.

Step-by-step explanation:

Given : The expression is 8x^{2} -7xy+3

To find : The value of expression if x=0, y=3.

Solution :

  • The given quadratic equation is,

       8x^{2} -7xy+3

  • We have to find the value of expression if x=0, y=3.
  • To find the value, put x=0, y=3 in given expression.
  • So, the given expression is,

      8x^{2} -7xy+3

  • Putting x=0, y=3 in given expression, we get

     8x^{2} -7xy+3 = 8(0)^{2} -7*0*3+3

                        =0-0+3

                        = 3

  • ∴ The value of 8x^{2} -7xy+3 at x=0, y=3 is 3.
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