Question

2. If x = 1/v2 , find the value of x³–3x²–5x+3
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Answer 1

Answer:

The answer is 4

Step by step explanation:

x = 1/√5 - 2

x = 1/√5 -2 × √5 + 2/√5 + 2

x = √5 + 2/ 5 - 4 = √5 - 2

x² = (√5 + 2)²

=> (√5)² + 2 × √5 × 2 + (2)²

=> 5 + 4√5 + 4

=> 9 + 4√5

Now,

x³ - 3x² - 5x + 3

=> (√5 + 2)(9 + 4√5) - 3(9+4√5) - 5(√5 + 2) +3

=> 9√5 + 20 + 18 + 8√5 - 27 - 12√5 - 5√5 - 10 + 3

Therefore the answer is 4.

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