2. If x is a negative integer such that distance between (x,3) and (5,9) is 10 units, then
(a) 13
(C) 3
(b)-3
(d) -13
please clear fast
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Answer:
(x-5)²+(3-9)²=10²=100
or, (x-5)²+36=100
or, (x-5)²=100-36=64
or, x-5= -8(as x is a negative integer)
or, x= -3
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