Question

2 If x + y = 10 and xy = 21, find 2(x2 + y2).​

Answer 1

Step-by-step explanation:

Step-by-step explanation:THE ANSWER IS GIVEN IN THE ATTACHMENT

Answer 2

Answer:

116

Step-by-step explanation:

Given :

x + y = 10

xy = 21

We can use this formula:

$(x+y)^2=x^2+2xy+y^2\\\\\\(x+y)^2=x^2+y^2+2xy\\\\\\(10)^2=x^2 + y^2 + 2(21)\\\\\\100=x^2+y^2+42\\\\\\100-42=x^2+y^2\\\\\\58=x^2+y^2$

Therefore,

$=2(x^2+y^2)\\\\\\=2(58)\\\\\\=116$

Hope it helps you :)