Question

2. If x:y= 3:2 find
(2x+3y) : ( 3x+ 5y)

3-. Two numbers are in the ratio 5:6 . If 8 is subtracted from each , the ratio becomes 4:5. Find the numbers.

4-. Two numbers are in the ratio 3:4 . If their LCM is 180, find the numbers.
HELP ME GUYS ANSWER THE QUESTIONS...​

Answer 1

Answer:

Step-by-step explanation:

2. : LET X=3k the y = 2k

so 2x +3y = 12k

     3x +5y = 19k

Req ratio: 12/19

3.    x = 5k   y = 6k

     (5k - 8)/(6k-8) =4/5

  cross multiply to get 25k -40 = 24k - 32 => k = 8

  so numbers are (40,48)

3. assmue the 3k and 4k

   there CLEARLY there hcf would be k(assumin k>3 and 4)

   Its know that HCF x LCM = PRODUCT of given numbers

                       so 180k = 12k^2

                       k = 15

                       hence the numers are 45 and 60