Math, asked by sabeehakhan089, 1 year ago

2) Ifa-b=7. ab = 5 find a² + b^2?​

Answers

Answered by rajdeepshaw968
2

Answer:

(a-b)^2=49

a^2-2ab+b^2=49

a^2+b^2=49+2ab

a^2+b^2=49+2×5

a^2+b^2=59.

Step-by-step explanation:

Answered by ItzAditt007
1

YOUR ANSWER IS 59.

EXPLANATION:-

Given:-

  • a-b = 7,
  • a-b = 7,And
  • a-b = 7,Andab = 5

To find:-

a²+b².

Now,

a-b = 7

Lets add square both sides so that we get a² and b².

---> (a-b)² = (7)².

---> a²-2ab+b² = 49.

{Since (x-y)² = x²-2xy+b²}

---> a²+b² = 49+2ab.

{Transporting -2ab to RHS}

---> a²+b² = 49+2(5).

{Since it is given that ab = 5}

---> a²+b² = 49+10.

---> a²+b² = 59.

Therefore a²+b² = 59.

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