Question

2. IFP, Q are the lengths of the
perpendiculars from the origin to the
straight lines
xseca + ycoseca = a and xcosa -
ysina = acos2a, prove that
4p2 + q2 = a.​

Answer 1

Answer:

proved

Step-by-step explanation:

xseca + ycoseca - a  = 0

xcosa -  ysina - acos2a = 0

P² = a² ÷ sec²a + cosec²a = a² sin²acos²a ÷ 1 = a² sin²acos²a

4P² = 4a² sin²acos²a = a² sin²2a

Q² = a²cos²2a ÷ 1 = a²cos²2a

4p2 + q2 = a²