Question

2.
IfQ (hk) is the image of the point P(x,y) w.I.t the straight line ox+by+C =0, then
(h-x):a=(x - y):5=-2(2x + by +c): (a +6°and
find the image of (1.-2) with respect to the straight line 2x - 3y + 5 = 0

Answer 1

Step-by-step explanation:

−1

=

−3

k+2

=

(2)

2

+(−3)

2

−2((2×1)−3(−2)+5)

2

h−1

=

−3

k+2

=

13

−2(13)

=−2

2

h−1

=−2

h=−3

−3

k+2

=−2

k=−8

∴point≡(−3,−8)