Math, asked by aribanaqvi76, 5 hours ago

2 (iii) 100000 for 9 months at 4% per annum compounded quarterly. ​

Answers

Answered by ranapratap9721
0

Answer:

It is given that 

Principal (P) = 100000

Rate of interest = 4% p.a. or 1% quarterly 

Period (n) = 9 months or 3 quarters 

We know that 

 P(1+r/100)n 

Substituting the values 

= 100000(1+1/100)3

By further calculation 

=100000×101/100×101/100×101/100

= 103030.10

Here 

CI = A - P

Substituting the values 

= 103030.10−100000

= 3030.10

Step-by-step explanation:

hope it will help full for you

Answered by mahisriguntur
0

Step-by-step explanation:

It is given that 

Principal (P) = 100000

Rate of interest = 4% p.a. or 1% quarterly 

Period (n) = 9 months or 3 quarters 

We know that 

 P(1+r/100)n 

Substituting the values 

= 100000(1+1/100)3

By further calculation 

=100000×101/100×101/100×101/100

= 103030.10

Here 

CI = A - P

Substituting the values 

= 103030.10−100000

= 3030.10

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