Question

2. In a A ABC, if angle A-B = 40° and angle B-C = 10°, find the measure of angle A,B,C​

Answer 1

Answer:

A=90°

B=50°

C=40°

Step-by-step explanation:

A - B = 40°

A = 40° + B

B - C = 10°

B - 10° = C

A + B + C = 180°

40° + B + B + B - 10° = 180°

3B + 30° = 180°

3B = 180° - 30°

B = 150°/3 = 50°

A = 40° + B = 40° + 50° = 90°

B = 50°

C = B - 10° = 50° - 10° = 40°