Question

2) In a Δ ABC, ˂A + ˂B = 110 degrees, ˂C + ˂A = 135 degrees. Find

˂A.​

Answer 1

Answer:

65°

Step-by-step explanation:

Since<A+ < B = 110° , < C must be 70° ( 180°- 110°)

and < C+ < A = 135 ° Then < B must be 45° ( 180° - 135° )

Hence < C+ <B = 115°

< A = (180°- 115°)= 65°