Math, asked by ammusivan38, 1 month ago

2. In A ABC, <B = 90°, AB= 13cm, AC= 21cm
BC=--------​

Answers

Answered by cherry7510
2

by pythagorous theorem,

21²=13²+BC²

441-169=BC²

272=BC²

BC=4√17

Answered by gorachandhansda405
0

Step-by-step explanation:

  • Here, In ABC
  • Angle B = 90°
  • So, ABC IS A RIGHT ANGLE TRIANGLE.
  • Now, AB = 13 cm
  • AC = 21 cm
  • BC = ?
  • By pythagores theorem ,
  • Hypotenuse^2 = Base^2 + Perpendicular^2
  • AC ^2 = BC ^2 + AB^2
  • 21^2 = BC^2 + 13^2
  • 441 = BC^2 + 169
  • BC^2 = 441-169
  • BC = 272=16.5cm (approx)
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