Question

2)
In A ABC, P is any point inside A ABC. Prove that AB + AC > BP + PC.
D.​

Answer 1

Step-by-step explanation:

Given ABC is a trianlge in which AB=AC . P is any point in the interior of the triangle such that angle ABP=ACP

In ΔAPB and ΔAPC,

AB=AC[given]

∠ABP=∠ACP [given]

AP=AP[common]

ΔAPB≅ΔAPC[by SAS congruency criterion]

∴∠PAB=∠PAC [corresponding angles of congruent trianlges]

thus, BP=CP

And AP bisects ∠BAC

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