2. In A ABC, right-angled at B, if AB = 12 cm and
BC =5 cm, find (i) sin A, tan A (ii) sin C, tan C.
tanya280606:
hlo dear, see my answer it is well explained hope it will be helpful.
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Answered by
0
Answer:
AC
thus
=
12
2
+5
2
=13
sinA=
AC
BC
=
13
5
tanA=
AB
BC
=
12
5
sinC=
AC
AB
=
13
12
cotC=
AB
BC
=
12
5
plz correct explaination kro
I don't have notes know so I can't write in paper and explain
what I wrote understand
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Your answer is in the above attachment.
HOPE IT IS HELPFUL......
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