Question

2. in a coil of self induction 5h, the rate of change of current is 2as-1. The emf induced in the coil is

Answer 1

e=L di/dy

5*2/1 = 10v

Answer 2

Dear Student,

◆ Answer -

E.M.F. = 10 V

● Explanation -

# Given -

L = 5 H

di/dt = 2 A/s

# Solution -

E.M.F. induced in thr coil is given by -

E.M.F. = L.di/dt

E.M.F. = 5 × 2

E.M.F. = 10 V

Hence, E.M.F. induced in the coil by current is 10 V.

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