Question

2) In a field, diy fodder for the cattle is heaped in a cuma
height of the cone is 1.4 m, and the radius of buses
the
is to be covered by a waterproof cloth in
lo
much minimum cloth is needed​

Answer 1

Answer:

Given: Height of the heap (h) = 2.1 m, diameter of the base (d) = 7.2 m ∴ Radius of the base (r) = d/2 = 7.2/2 = 3.6 m To find: Volume of the heap of the fodder and polythene sheet required i. Volume of the heap of fodder = (1/3) πr2h = (1/3) x (22/7) x (3.6)2 x 2.1 = (1/3) x (22/7) x 3.6 x 3.6 x 2.1 = 1 x 22 x 1.2 x 3.6 x 0.3 = 28.51 cubic metre ii. Now, l2 = r2 + h2 = (3.6)2 + (2.1)2 = 12.96 + 4.41 ∴ l2 =17.37 ∴ l2 = √17.37 ... [Taking square root on both sides] = 4.17 m iii. Area of the polythene sheet needed to cover the heap of the fodder = Curved surface area of the conical heap = πrl = (22/7) x 3.6 x 4.17 = 47.18 sq.m ∴ The volume of the heap of the fodder is 28.51 cubic metre and a polythene sheet of 47.18 sq.m will be required to cover it.Read more on Sarthaks.com - https://www.sarthaks.com/853017/field-dry-fodder-for-the-cattle-heaped-conical-shape-the-height-the-cone-and-diameter-base