2. In a knockout competition of badminton in which 64 players participated. We form pairs of
competitors and in each round the losers are eliminated. While the winners reach the next
round. In each round the number of players(competitors) is reduced to half. Represent the
number of players left after each round in exponential notation in a tabular form.
Answers
Given : In a knockout competition of batminton 64 plaers participated .
In each round loosers are eliminated while the winners reach the next round. in each round number of players are reduced to half.
To Find : Represent the number of players left after each round in exponential notation in a tabular form
Solution:
Player in 1st Round = 64
Player after 1st round = 64/2 = 32
Player after 2nd round = 32/2 = 16
Player after 3rd round =16/2 = 8
Player after 4th round = 8/2 = 4
Player after 5th round = 4/2 = 2
Player after 6th round = 2/2 = 1 ( Winner)
64 = 2 * 2 * 2 * 2 * 2 * 2 = 2⁶
32 = 2 * 2 * 2 * 2 * 2 = 2⁵
16 = 2 * 2 * 2 * 2 = 2⁴
8 = 2 * 2 * 2 = 2³
4 = 2 * 2 = 2²
2 = 2¹
1 = 2⁰
Round Player after round
1 2⁵
2 2⁴
3 2³
4 2²
5 2¹
6 2⁰
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