Question

2. In a morning walk, three boys step off together from the same spot. Their steps measure 63 cm, 70 cm and 77 cm respectively. What is the minimum distance each should cover so that all can cover the same distance in complete steps? is the least distance in which both​

Answer 1

Step-by-step explanation:

hlo mate here's your answer

Step measure of

Step measure of 1 st

Step measure of 1 stBoy

Step measure of 1 stBoy=

Step measure of 1 stBoy=63

Step measure of 1 stBoy=63cm

Step measure of 1 stBoy=63cmStep measure of 2

Step measure of 1 stBoy=63cmStep measure of 2nd

Step measure of 1 stBoy=63cmStep measure of 2ndBoy

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cm

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rd

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cm

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×5×

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×5×7×

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×5×7×11=

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×5×7×11=6930

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×5×7×11=6930Hence, the minimum distance each should cover so that all can cover the distance in complete steps is 6930 cm.

Step measure of 1 stBoy=63cmStep measure of 2ndBoy=70cmStep measure of 3 rdBoy=77cmLCM of 63,70,77LCM=2×3×3×5×7×11=6930Hence, the minimum distance each should cover so that all can cover the distance in complete steps is 6930 cm.2

I hope its help you mark as brainlist plz and

Answer 2

Here, the required minimum distance will be equal to the LCM of measures of their steps.

Step measure of 1st Boy = 63 cm

Step measure of 2nd Boy = 70 cm

Step measure of 3rd Boy = 77 cm

LCM of 63,70,77

→ 63 = 3² × 7

→ 70 = 2 × 5 × 7

→ 77 = 7 × 11

LCM=2 × 3² × 5 × 7 × 11 = 6930

• Hence, the minimum distance each should cover so that all can cover the distance in complete steps is 6930 cm.