Question

2. In a parallel plate capacitor with air
between the plates, each plate has an
area of 6 x 10-3 m² and the separation
between the plates is 2 mm. a) Calculate
the capacitance of the capacitor, b) If this
capacitor is connected to 100 V supply,
what would be the charge on each plate?
c) How would charge on the plates be
affected if a 2 mm thick mica sheet of
k = 6 is inserted between the plates while
the voltage supply remains connected ?
[Ans: (a) 2.655 x 10-11 F,
(b) 2.655 x 10-9 C, (c) 15.93 x 10°C]
X​

Answer 1

Answer:

Area of each plate A=6×10

−3

m

2

Distance between the plates d=3mm=0.003m

Capacitance of capacitor C=

d

Aϵ

o

∴ C=

0.003

6×10

−3

×8.85×10

−12

=17.7pF

Voltage across the capacitor V=100 volts

Thus charge on each plate Q=CV

∴ Q=17.7×10

−12

×100

⟹ Q=1.77×10

−9

C

Explanation:

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