Question

2. In a population that is in Hardy-Weinberg equilibrium, the frequency of the
homozygous recessive genotype is 009. What is the frequency of individuals that are
homozygous for the dominant allele?​

Answer 1

Explanation:

i think the question is not correct. it cant be 009 but if it is .009 so the ans will be .991

here u go with solution,

q^2 = .009

p^2=1-q^2

=1- 0.009

p^2=0.991