Question

2) in a ∆ PQR, LQ= 90° and PQ= 7cm , QR=12cm. find tan P.​

Answer 1

Answer:

In a ∆ PQR, LQ= 90° and PQ= 7cm , QR=12cm.

tan tetha = opposite /adjacent

tan P = QR / PQ

tan P = 12 / 7

Answer 2

Answer:

Answer is 12/7

Step-by-step explanation:

In a ∆ PQR, LQ=90°and PQ=7cm , QR=12 cm,

Tan terha=opposite/adjacent

Tan P=OR/PQ

Tan P=12/7