Question

2) In A PQR, m_P=60", m_R =30', m_Q = 90°
If hypotenuse PR =16cm
Then find QR
$
or
9​

Answer 1

QR/PR= cosR

QR/16= cos30

QR/16= (√3)/2

QR=8√3. cm

Answer 2

∆pqr is a right angled at q =90 R,=30 sec 30 2/√3 = 16/ qr ( cross multiplication) =2qr =16√3

qr=16√3/2 ,qr=8√3