Chemistry, asked by shrushti49, 4 months ago


2
In a reaction, 2X - Y, the concentration of)
decreases from 0.50 M to 0.38 M in 10 min
What is the rate of reaction in Ms-1 during
this interval?
(a) 2 x 10-4
(b) 4 x 10-2
(C) 2 x 10-2
(d) 1 x 10-2


Answers

Answered by tinyriju2006
0

Answer: 2x10^-4

Explanation:

Rate of reaction =  

△[X]/△t

△[X]=Xi −Xf  =0.50−0.38=0.12 M

Rate=  

0.12/10×60

 =2×10^ −4  M s  ^−1  .

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