2. In a rhombus PQRS if PQ = 7.5 then find QR.
If angle QPS = 75° then find the measure of angle PQR and angle
SRQ.
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Sum
In a rhombus PQRS if PQ = 7.5 then find QR. If ∠QPS = 75° then find the measure of ∠PQR and ∠SRQ.
SOLUTION
All the sides of a rhombus are equal.
So, PQ = QR = 7.5 cm
A rhombus is also a parallelogram so,
∠QPS = ∠SRQ = 75°
(opposite angles of a parallelogram are congruent)
Also, ∠QPS + ∠PQR = 180°
(interior angles on the same side of the transversal are supplementary)
⇒ 75° + ∠ PQR = 180°
⇒ ∠PQR = 105°
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Answer:
so pQ = QR = 7.5 cm. A rhombus is also a parallelogram so,. ∠QPS = ∠SRQ = 75° (opposite angles of a parallelogram are congruent). Also, ∠QPS + ∠PQR ...
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