Math, asked by mugdhakhanolkar6, 28 days ago

2. In a rhombus PQRS if PQ = 7.5 then find QR.
If angle QPS = 75° then find the measure of angle PQR and angle
SRQ.​

Answers

Answered by ixvenukumar
5

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Sum

In a rhombus PQRS if PQ = 7.5 then find QR. If ∠QPS = 75° then find the measure of ∠PQR and ∠SRQ.

SOLUTION

All the sides of a rhombus are equal.

So, PQ = QR = 7.5 cm

A rhombus is also a parallelogram so,

∠QPS = ∠SRQ = 75°

(opposite angles of a parallelogram are congruent)

Also, ∠QPS + ∠PQR = 180°

(interior angles on the same side of the transversal are supplementary)

⇒ 75° + ∠ PQR = 180°

⇒ ∠PQR = 105°

Answered by sadhnasingh52771
5

Answer:

so pQ = QR = 7.5 cm. A rhombus is also a parallelogram so,. ∠QPS = ∠SRQ = 75° (opposite angles of a parallelogram are congruent). Also, ∠QPS + ∠PQR ...

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