Question

2. In a triangle ABC, E and F respectively are mid-
points of equal sides AB and AC of AABC. Show that
BF = CE.​

Answer 1

Answer:

Given E and F are mid point of equal sides AB and AC of triangle ABC

In ΔABF and ΔACE

AB=AC (given )

∠A=∠A (common angle )

AF=AE (halves of equal sides)

∴ΔABF≅ΔACE (SAS rule)

∴BF=CF (CPCT)

I hope it help you..