2. In AABC, AD is the bisector of A meeting side BC at D, if AB = 10cm, AC = 14cm and BC = 6cm,
find BD and DC
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Let DB = x , then CD = 6 - x
AB/AC = DB/CD
10/14 = x/(6 - x )
5/7 = x/(6 - x )
5(6 - x ) = 7x
30 - 5x = 7x
7x + 5x = 30
12x = 30
x = 30/12 = 5/2 = 2.5
BD = 2.5 cm and CD = 6 - 2.5 = 3.5 cm
Hope this would help
AB/AC = DB/CD
10/14 = x/(6 - x )
5/7 = x/(6 - x )
5(6 - x ) = 7x
30 - 5x = 7x
7x + 5x = 30
12x = 30
x = 30/12 = 5/2 = 2.5
BD = 2.5 cm and CD = 6 - 2.5 = 3.5 cm
Hope this would help
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1
Hi anna/thambi
Enna panringa
Entha ooru
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