Question

2)In AABC, LA = 90°, ADIBC AB= 20cm and AC= 15 cm, then find the length of AD. A D BZ​

Answer 1

Answer:

refer to the attachment

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

In ΔABC, AD=6cm and BC=9cm

$AREA \: OF \: TRIANGLE= \frac{1}{2} \times base \times height = \frac{1}{2} \times bc \: ad$

,

$\frac{1}{2} \times 9 \times 6 = 27cm {}^{2}$

$Again, Area of triangle= \frac{1}{2} ×base×height= \frac{1}{2} ×AB×CE$

$⇒27= \frac{1}{2} ×7.5×CE$

$ce = \frac{27 \times 2}{7.5}$

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm