Question

2. In AABC,right-angled at B, AB=24cm, BC=7cm, then Sin A=
O 7/25
O24/25
O 25/24
025/7​

Answer 1

Answer:

sinA=opposite to A/hypotenuse

=7/25

Answer 2

Answer:

sinA= 7/25 ;

Step-by-step explanation:

Given:AB=24, BC=7

By using pythagoras theorem,In rt. triangle ABC,

(AB)^2+ (BC)^2 = (CA)^2

Or, (24)^2+(7)^2=(CA)^2

Or, CA= √(576+49)

Or, CA= √(625)

Or, CA = 25 cm

Now,

• We know that,

$\sin( \alpha ) = \frac{perpendicular}{hypotenuse}$

therefore, sinA = BC/CA ;

Hence, SinA= 7/25;

• [pls appreciate♡ the answer if you find helpful..ty]