2. In AABC,
seg AD 1 seg BC,
DB = 3CD.
Prove that 2ABP = 2AC2 + BC2
Answers
Answered by
3
AD ⊥BC and BD = 3CD ... 9CD2 = 8(BC/4)2 [Since, BC = DB + CD = 3CD + CD = 4CD] ... 2AB2 = 2AC2 + BC2. 4.4.
Similar questions
Chemistry,
4 months ago
Computer Science,
4 months ago
Environmental Sciences,
9 months ago
Science,
11 months ago
Math,
11 months ago
Business Studies,
11 months ago