Math, asked by waghaditya101, 9 months ago

2. In AABC,
seg AD 1 seg BC,
DB = 3CD.
Prove that 2ABP = 2AC2 + BC2

Answers

Answered by subhalaxmimohanty085

3

AD ⊥BC and BD = 3CD ... 9CD2 = 8(BC/4)2 [Since, BC = DB + CD = 3CD + CD = 4CD] ... 2AB2 = 2AC2 + BC2. 4.4.

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