2. In ΔABC, angle B -90°. Dis the mid-point of AB andDE II BC. If AB=9 cm and AC = 15 cm, find the
perimeter of DECB.
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Answered by
12
Step-by-step explanation:
By using pythagorous theorem we find BC=12cm.
√AC²-AB²=BC
AB/AD=BC/DE
9/4.5=12/DE
DE =6cm...........................................................(1)
AB/AD=AC/EC
9/4.5=15/EC
EC=7.5cm................................................(2)
DB=1/2 of AB
perimeter of DEBC= DB +BC+ EC +DE
DEBC=4.5+ 12 +7.5 +6
DEBC=30 cm.
hope it will help you.......
Answered by
7
answer is 30 cm
hope it' helps:))))))
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