2
In ∆ ABC if AB²= AC²+ CB² state with
reason whether ∆АВС is a right triangle or
not,
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AB²=2 AC² can be written as AB²= AC²+AC² It looks like Pythagoras theorem. AB is the hypotenuse and AC and BC are sides which are equal. Hence we can represent BC as AC. So it must be right angled isosceles triangle with right angle at C.
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