Question

2
In ∆ ABC right angled at B if tan
A = 1/√3 Find value of sinAcosc
+ cosAsinc.
​

Answer 1

Answer:

7/12

Step-by-step explanation:

A

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B        C

As tanA = 1/√3, therefore A = 30°

A = 30°, B = 90°, C = 60°

sinAcosC + cosAsinC

(sin30°)(cos60°) + (cos30°)(sin60°)

(1/2)(1/2) + (1/√3)(1/√3)

= 1/4 + 1/3 = 7/12

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