2. In an A.P the 10th term is 46, sum of the 5th and 7th term is 52. Find the A.P.
Answers
Answered by
1
Answer:
a = 1
d = 5
A.P. = 1 , 6 , 11 , 16...
Step-by-step explanation:
5th term = a + 4d
7th term = a + 6d
Sum of 5th and 7th term = 52 (Given)
a + 4d + a + 6d = 52
2a + 10d = 52 ⇒ a + 5d = 26 ...(i)
10th term = 46 (Given)
a + 9d = 46 ...(ii)
Subtracting (i) from (ii)
4d = 20 ⇒ d = 5
a + 9d = 46
a + 9(5) = 46
a = 46 - 45
a = 1
Hope this answer helps you.
Answered by
0
Answer:
a10=46
a5+a7=52
a+9d=46----->1
a+6d=26----->2
=> 3d=20
=>d=20/3
substitute d value in 2
we get
a=26-40=-14
therefore, the required AP is,
-14,-22/3,-1,17/3.......
Step-by-step explanation:
note:-SOME STEPS ARE SKIPPED....
HOPE IT HELPS U
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