Question

2. In an A.P., the sum of three consecutive terms is 24 and their product is 312. Complete the following
activity to find the terms. (The terms in A.P. are in ascending order).
Let the three consecutive terms in the A.P.
be a-d. a and ad
From the first condition,
Page: 1
(a - d) + a + (a + d)=
3a =
From the second condition.
(4-2)*a* (a + 2) =
(8 - 4) * 8 x (8+d)=D (Substituting the value of 2)
...(Dividing both the sides by 8)
(8 - d) (8+2) =
64-d` = 39 d = 64 – 39 d = 25
...(The value of d is positive. Why?)
8​

Answer 1

Step-by-step explanation:

Your required answer is here

Let the three consecutive terms in the A.P.

be a-d. a and ad

From the first condition,

Page: 1

(a - d) + a + (a + d)= 24

3a = 24

a=8

From the second condition.

(a-d)×a×(a+d) = 312

(8 - d) × 8 × (8+d)=D (Substituting the value of 2)

(8 - d) (8+d) = 312÷8

8^2-d^2 = 39

64-d^2=39

64-39=d^2

25=d^2

d= 5 or -5

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