2.
In an arithmetic progression, if
an
2n +1, then the common difference
of the given progression is
Answers
Given : In an arithmetic progression aₙ = 2n + 1
To find : the common difference of the given progression
Solution:
aₙ = 2n + 1
aₙ₊₁ = 2(n+1) + 1 = 2n + 2 + 1
=> aₙ₊₁ = 2n + 2 + 1
=> aₙ₊₁ = 2n + 3
Common Difference of an AP
= aₙ₊₁ - aₙ
= 2n + 3 - (2n + 1)
= 2n + 3 - 2n - 1
= 3 - 1
= 2
Hence Common Difference of AP = 2
Another way n = 1
=> a₁ = 2(1) + 1 = 3
a₂ = 2(2) + 1 = 5
Common difference =
a₂ = a₁ + d
=> 5 = 3 + d
=> d = 2
Hence AP = 3 , 5 , 7 , 9 ,,,,,,,,,,,,,,,,,,,,,
common difference of the given progression = 2
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