Question

2
In an experiment 0.243 g of Mg gives 0.403 g
of Mgo, in another case 0.182 g of Mg reacts
with O2 to give 0.120 g of Mgo then
Prove law of constant proportione​

Answer 1

Answer:

Experiment 1: Weight of Magnesium oxide =0.4030 gm

Weight of Magnesium =0.2430 gm

Weight of oxygen=0.4030–0.2430=0.16 gm

Ratio of Magnesium: oxygen =0.2430:0.16=1.552:1

Experiment 2:

Weight of Magnesium oxide=0.3020

Weight of Magnesium =0.1820

Weight of oxygen =0.3020–0.1820=0.12

Ratio of magnesium: oxygen=0.1820:0.12=1.552:1

In both experiments the ratio of magnesium: oxygen is same (1.518:1)

Hence, it illustrates the law of definite proportions.

Explanation:

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