Question

2
In an isosceles triangle ABC
А) ab =AC =10 cm and BC =18 cm
find the value
Sin ² B + Cos2 C
ta 2 c - sec2 B +2​

Answer 1

Answer:

your answer is 1

Step-by-step explanation:

we know that ∆B = ∆C

= sin^2B + cos^2 C = 1

= tan^2C - sec^2B = -(sec^2B - tan^2B)

-1+2=1