Question

2. In angleABC, angleA: angleB: angleC = 4:5:6. Calculate angleA, angleB and angleC.​

Answer 1

Answer:

Angle A = 48

Angle B = 60

Angle C = 72

Step-by-step explanation:

let the angle be - x

then ,

Angle A- 4x

Angle B - 5x

Angle C - 6x

total angel in an triangle - 180 °

so,

180 = 4x+5x+6x

180 = 15x

180/15 = x

x = 12

So, if x is equal to 12 then

Angle A = 4 × 12 = 48

Angle B = 5 × 12 = 60

Angle C = 6 × 12 = 72

Answer 2

Step-by-step explanation:

A:B:C =4:5:6

let x be some angle

as we know that sum of all angles in a triangle = 180°

so, 4x+5x+6x = 80°

5x=180

x=12°

hence, reuired angles are A: 4×12=48°

B: 5×12=60°

C: 6×12=72°

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