Question

2) In APQR, Q=90°, PQ = 8 cm and QR = 15 cm, then find the length of PR​

Answer 1

Answer:

as angle Q = 90°

hence.

(PR)^2 = (QR)^2 + (PQ)^2

PR^2 = 15×15+8×8

PR =

$\sqrt{225 + 64 }$

PR =

$\sqrt{289}$

PR = 17cm this would be your answer.

hope it helps you

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Answer 2

Given

In triangle PQR, PQ= 8 cm QR= 15 cm and Q= 90

therefore it is right angle triangle.

Pythagoras theorem

$p {}^{2} = h {}^{2} + b {}^{2}$

where p is PR or hypotenuse, h is PQ or height and b is QR or base.

$p {}^{2} = 8 {}^{2} + 15 ^{2} \\ p { }^{2} = 64 + 225 \\ p {}^{2} = 289 \\ p = \sqrt{289 } \\ p = 17$

p = PR

PR = 17 cm